If th is a theorem of the form returned by the function
define_new_type_bijections:
|- (!a. abs(rep a) = a) /\ (!r. P r = (rep(abs r) = r))
then prove_rep_fn_onto th proves from this theorem that the
function rep is onto the set of values that satisfy P, returning the
theorem:
|- !r. P r = (?a. r = rep a)