When applied to a variable x and a theorem whose conclusion is
equational, A |- t1 = t2, the inference rule
EXISTS_EQ returns the theorem A |- (?x. t1) = (?x. t2), provided
the variable x is not free in any of the assumptions.
A |- t1 = t2
------------------------ EXISTS_EQ "x" [where x is not free in A]
A |- (?x.t1) = (?x.t2)